泳池(chi)熱(re)泵利用(yong)熱(re)泵技術回收低位熱(re)能（包括顯熱(re)和潛熱(re)）用(yong)于室(shi)內游(you)泳池(chi)，與室(shi)內空(kong)(kong)調降溫(wen)（或供熱(re)）和除(chu)濕結(jie)合，做(zuo)到(dao)“一機三(san)用(yong)”達(da)到(dao)空(kong)(kong)調、除(chu)濕、泳池(chi)恒溫(wen)加熱(re)的(de)目的(de)。下(xia)面介紹泳池(chi)除(chu)濕熱(re)泵的(de)運行(xing)計算方法。

泳池(chi)(chi)除濕(shi)熱(re)(re)泵的工(gong)作原理:泳池(chi)(chi)熱(re)(re)泵將(jiang)(jiang)室內游(you)泳池(chi)(chi)蒸(zheng)發到(dao)(dao)空(kong)氣(qi)中(zhong)的水(shui)蒸(zheng)汽(qi)（空(kong)氣(qi)潛熱(re)(re)）回收利用(yong)起來，首先通過熱(re)(re)泵將(jiang)(jiang)室內潮(chao)濕(shi)空(kong)氣(qi)（回風）降(jiang)低溫度至(zhi)露(lu)點，使(shi)空(kong)氣(qi)中(zhong)的水(shui)蒸(zheng)汽(qi)凝(ning)結(jie)成(cheng)水(shui)，使(shi)空(kong)氣(qi)干燥達到(dao)(dao)除濕(shi)的效果，并放(fang)出熱(re)(re)量(liang)(liang)。其次將(jiang)(jiang)放(fang)出的熱(re)(re)量(liang)(liang)轉移給泳池(chi)(chi)水(shui)加(jia)熱(re)(re)和(he)即將(jiang)(jiang)返回室內的空(kong)氣(qi)（增加(jia)空(kong)氣(qi)的顯熱(re)(re)）；最終(zhong)將(jiang)(jiang)多余的熱(re)(re)量(liang)(liang)通過室外冷(leng)凝(ning)器排(pai)至(zhi)室外，實(shi)現了室內泳池(chi)(chi)池(chi)(chi)水(shui)加(jia)熱(re)(re)、空(kong)氣(qi)除濕(shi)的目的。

泳(yong)池(chi)(chi)除(chu)濕(shi)(shi)的同(tong)時可將一部分(fen)熱(re)量(liang)轉移到加(jia)熱(re)池(chi)(chi)水(shui)中。國外資料(liao)表明，私人游泳(yong)池(chi)(chi)的產(chan)濕(shi)(shi)量(liang)為(wei)(wei)：每(mei)平(ping)方米(mi)水(shui)面面積0.10-0.15kg/h.m2 ,再加(jia)上每(mei)人0.40-0.50kg/h。每(mei)平(ping)方米(mi)水(shui)面每(mei)年產(chan)生(sheng)的水(shui)蒸氣約為(wei)(wei)1t，每(mei)噸水(shui)蒸氣相當熱(re)量(liang)約為(wei)(wei)700KW.h。為(wei)(wei)除(chu)濕(shi)(shi)所需(xu)的通風量(liang)約為(wei)(wei)25－40m3/m2.h。泳(yong)池(chi)(chi)除(chu)濕(shi)(shi)熱(re)泵除(chu)濕(shi)(shi)加(jia)熱(re)過程(cheng)可以從h-d圖上作圖說明（見(jian)圖2）。

圖(tu)(tu)2 除濕過程在h-d圖(tu)(tu)上的表示

傳統除(chu)(chu)濕，室內(nei)空(kong)(kong)氣(qi)狀態(tai)點(dian)(dian)(dian)P（假定28℃、φ＝50％）與新風點(dian)(dian)(dian)A（假定＋5℃、φ＝90％）混合(he)，混合(he)點(dian)(dian)(dian)M，再由M點(dian)(dian)(dian)加(jia)熱(re)(re)(re)到E點(dian)(dian)(dian)（46℃、φ＝13％），加(jia)熱(re)(re)(re)過程所需(xu)熱(re)(re)(re)量為(wei)QC；熱(re)(re)(re)泵(beng)除(chu)(chu)濕，由于(yu)熱(re)(re)(re)泵(beng)吸取P狀態(tai)下空(kong)(kong)氣(qi)的熱(re)(re)(re)量，使空(kong)(kong)氣(qi)降溫降濕至(zhi)K點(dian)(dian)(dian)（假定10℃、φ＝80％），再用冷凝熱(re)(re)(re)將(jiang)空(kong)(kong)氣(qi)加(jia)熱(re)(re)(re)至(zhi)E點(dian)(dian)(dian)（送風狀態(tai)），空(kong)(kong)氣(qi)的得熱(re)(re)(re)量為(wei)（hE－hK）×Vγ＝Qhp。設(she)熱(re)(re)(re)泵(beng)的能(neng)效比COP＝3.8,則熱(re)(re)(re)泵(beng)實際耗電量僅為(wei)0.263Qhp。如Qhp>QC，則熱(re)(re)(re)泵(beng)的制(zhi)熱(re)(re)(re)量除(chu)(chu)了加(jia)熱(re)(re)(re)空(kong)(kong)氣(qi)外，還可以有多余(yu)的熱(re)(re)(re)量，來加(jia)熱(re)(re)(re)池水。